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How do you ensure this? Email Required, but never shown. If no what’s the matter of my circuit?
On CMOS parts, all unused inputs must be connected, directly or through a resistor, to either Vcc or ground, whichever is required to make the part work as required. I’m building a simple ring counter with two jk flip-flop.
74HC76 Datasheet Renesas pdf data sheet FREE from
For the Preset pin where you have a switch to pull it to ground, you must also have a resistor 5K – 10K to Vcc to ensure the preset pin is high when the switch is not taking it low. Do not, ever, disconnect the VCC pin when debugging, because that breaks chips. Thanks for your advice. Without a resistor in series with each LED is is likely that the corresponding Q output is being dragged down to a voltage that is not high enough to be recognized as a legitimate high level by the following J input.
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About Preset and Clear pin I’m managing them well: Post as a guest Name. I’m using 74HC76 integrated that contains two jk. Home Questions Tags Users Unanswered.
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JK1 and JK2 need to initialize in opposite states, don’t they? Sign up using Email and Password. I’ve a button that sets the starting 1 in the first jk, so I think that the problem isn’t about Preset or Datasyeet pin.
The problem is that in the circuit that I’m observing on my desk the ring counter only works when pin 5 Vcc is unwired.
It means that if I wire pin 5 to Vcc I got always 10 output. This is my schematic very basic: Sign datashee using Facebook.